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We will now give some thought to the
second and third question raised
before: How much light is produced by
recombination? This raises the question for the value of the quantum
efficiency hqu mentioned before, and the total or
external efficiency hex in absolute terms (third
question). |
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First we will define the
quantum efficiency again (and
somewhat more specifically) and relate it to some other efficiencies. |
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The
quantum efficiency
hqu is defined as |
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| hqu |
= |
Number of photons generated in the recombination zone
Number of recombining carrier pairs in the recombination zone |
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We already know that, it
could be expressed as |
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| hqu = |
1
1 + trad /
tnon-rad |
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In the
high injection approximation the
number of carriers is about equal to the number of carriers injected (across a
junction) into the recombination zone. |
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That part of the total recombination occurring
via a radiative channel determines the quantum efficiency. However, the surplus
carriers in the recombination zone have one more "channel", not
considered so far, for disappearing from the recombination zone: They
simply move out! |
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In other words: parts of the injected carriers
will simply flow across the recombination zone and leave it at "the other
end". |
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This effect can be
described by the current
efficiency hcu; it is defined as |
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| hcu |
= |
Number of recombining carrier pairs in the recombination zone
Number of carrier pairs injected into the recombination zone |
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We now define the
optical efficiency
hopt as |
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| hopt |
= |
Number of photons in the exterior
Number of photons generated in the recombination zone |
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The optical efficiency takes care of the (sad)
fact that in most devices a large part of the photons generated become
reabsorbed or are otherwise lost and never leave the device. |
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The total or
external efficiency hex now simply is |
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If we want to optimize the external
efficiency, we must work on all three factor - none of them is negligible. |
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We already "know" how to optimize the
quantum efficiency hqu by looking
at the equation above. We must look for the best combination of materials
producing radiation at the desired wavelength, and then dope it in such a way
as to maximize the radiative channel(s) by minimizing the corresponding
lifetimes. While this is not easy to do in practice, it is clear in
principle. |
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We do not yet know how to attack the
two other problems: Maximized current efficiency and maximized optical
efficiency. And theses problems are far from being solved in a final, or just
semi-final way - intense world-wide research efforts center on new solutions to
these problems. |
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While there are no general solutions to these
problems and only some useful equations, a few general points can still be
made. We will do this in the remainder of this subchapter for the current
efficiency and in a separate subchapter
for the optical efficiency. |
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The question to ask is: Why is the
current efficiency not close to 1 in
any case? |
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After all, if we consider a simple
pn-junction biased in forward direction in a direct semiconductor (e.g.
GaAs), we inject electrons into the p-part and holes into the
n-part, where they will become minority carriers. Some of the injected
carriers will recombine in the space charge region, all others eventually in
the bulk region. |
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While the quantum efficiency may be different in
the different regions, because the strength of the recombination channels
depends on the carrier density which is not constant across the junction, we
still could assign some kind of mean quantum efficiency to the diode so that
hcu = 1. |
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However, we defined the efficiencies relative to
a "recombination zone", i.e we
are not interested in radiation produced elsewhere for various reasons (to be
discussed later). If we take the recombination zone to be identical to the
SCR, only that part of the injected carriers that recombines in the
SCR will contribute. |
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This is exactly that part of
the forward current that we had to introduce to account for real
I-V-characteristics of pn- junctions - cf. the
simple and
advanced version
in the relevant modules. |
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That part of the current that injects the
carriers which recombine in
the SCR was given by |
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| jrec (SCR) =
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e · ni ·
d
2t |
· exp |
e · U
2kT |
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d was the width of the
SCR. |
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The current efficiency in this case
would then be given by |
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| hcu
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= |
jrec
jdiode |
= |
jrec
jnon-rec + jrec |
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=
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1
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| 1 + |
jnonrec
jrec |
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With
jnon-rec (assuming that the electron and hole
contributions and parameters are equal) given by the
"simple"
diode equation as |
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| jnon-rec |
= |
2 · e · L · ni2
t · NDop |
· |
æ
ç
è |
exp |
e · U
kT |
1 |
ö
÷
ø |
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we obtain for hcu (neglecting the 1 after
the exponential) |
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hcu =
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1
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| 1 + |
4 L · t · ni
d |
· exp |
eU
kT |
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hcu
thus decreases exponentially with the applied voltage and it would not make
sense to include this effect in some averaged hqu . |
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Why are we looking at radiation only
from some confined part of the device, i.e. from the recombination zone, and not at the total volume,
which demanded a finer look at the efficiencies? There are practical reasons, e.g.: |
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If we consider a semiconductor Laser, only the radiation inside the "resonator" counts - everything outside of this
specific recombination volume is of little interest. |
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If we look at a light emitting diode - a
LED - made from GaP doped
with N (in addition to the normal doping) to produce the isolectronic
impurities needed to bind the excitons
responsible for the radiative recombination channel, it only radiates from the p-side because only electrons become primarily bound to the
isoelectronic impurity and than attract a hole. In other words, only the
electron part of the injected current will contribute to radiation. |
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We must confine light production to
areas close to the surface as shown
in the next subchapter. |
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Looking ahead we will learn that many
optoelectronic devices are extremely complicated heterostructures which, for
several reasons, need a precise definition of the
recombination volume. |
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Nevertheless, current efficiencies,
while helpful in thinking about devices and radiative processes, are relatively
hard to describe in detail. |
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If we accept that we want light only from a
defined recombination volume, we now can look at a simple way to understand the
current efficiency. If we look at the disappearance of the injected carriers,
we have the simple rate equation |
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dn
dt |
= |
1
q |
· div( j ) R
total |
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The first term describes the appearance or
disappearance of carriers because they flow in or out of the volume as a
current; the second term contains the recombination processes. |
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A high current efficiency then simply means to
make div( j ) as negative as possible for electrons and as
positive as possible for holes (remember that q = e
for electrons and + e for holes). In other words, maximize the flow of
carriers into the volume, and minimize the flow out of it. |
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© H. Föll