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When we make a contact to the
structures in the Si, for example to source and drain regions, we first cover
everything with an insulator - SiO2 - and then make contact
holes in the proper places. Use the
link to refresh
your memory. |
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Next we cover everything with a metal
- if we stay simple we just use Al. We have a lot of other processes
after that, and we will have to heat up the wafer to some extent for doing
whatever needs to be done. |
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What happens if we bring Si in
contact with Al (or any other metal, for that matter) and heat it up to
some extent? |
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Well - consult the phase diagram, and it will
tell you what you should expect at whatever temperature you chose. Here is the
Al - Si phase diagram. |
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What it tells us it that somewhat below 600
oC we will have an eutectic. |
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In other words, above the eutectic temperature,
"things" will melt. Consult the
chapter
about phase diagrams if you don't know exactly what "things"
means. |
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In yet other words, after Al deposition,
we must not raise the temperature above the eutectic temperature ever In order
to stay on the safe side, we must even keep it below about 500
oC |
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This is not so good, but something else is worse:
The solubility of Si in Al around 500 oC is
finite - about 2 % one would estimate - , while at room temperature it
is practically nil. |
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So what happens if you heat up
Al in contact to Si? The Al will try to incorporate some
Si; it will sort of "suck it up" from the Si
substrate. |
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In more scientific terms we talk about Si
atoms diffusing into the Al (and Al atoms diffusing into the
Si); so temperature dependent quantities like diffusion coefficients are
involved. |
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If we now have some of the Si in the
Al, it must be missing somewhere else; obviously right below the
Al-Si interface we must expect some "missing" Si. |
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If we are lucky, the "missing"
Si is uniformly distributed, i.e. the whole surface of the Si
moved down a bit. However, Murphy's law (What can go wrong will go wrong)
applies, and on occasion all the Si moving into the Al comes from
one rather localized spot at the interface - we get a "spike". This is shown very drastically in the
picture. |
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At the same time, Al will diffuse in the
room left by the Si - our spike is filled with Al and we have a
short-circuited pn-junction! |
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This ain't so good. Remember: One
spike / short circuit in just one of the > 50 million or so contact
holes will kill the whole IC. We must fix that problem. |
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Easy, you say. (Do you see the
obvious solution?). We do not use pure Al, but Al already
containing some Si, so it does not have to "steal" Si
from the substrate to meet its solubility needs at higher temperatures. |
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Right. That is exactly what we will
do. We use Al alloyed with 0.5% - 1 % of Si. No
more spikes will form, and as the process engineer in charge you can sleep well
again at night. |
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Really? Yes, you will. For a few
years at least. But then you slumber will become unruly again, because as
dimensions shrink, you run into new problem. |
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You use Al(0.7 % Si) as your
contact material. The dictate of the phase diagram with regard to the Aluminium
needs of Si at your highest temperature are met; no spiking will
occur. |
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How about the needs of the Al
at room temperature? They are not met, because Si solubility at room
temperature is negligible. |
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The phase diagram now dictates that
Si precipitates should form. This will need some nucleation and may be
kinetically difficult in the bulk of the Al, but at the Al-Si
interface we already have Si and nucleation is easy. |
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In essence, we must expect the
reverse of the "sucking Si into Al" process to take
place. The Al will "spit out" its surplus Si and deposit it
right at the interface |
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Si precipitates will grow
epitaxially (there is no reason why not) on
the Si below the Al. We must expect to find some Si
islands on top of the Si |
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That is exactly what we see in the
pictures above. |
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In the left hand picture we have a
nice balance of a few shallow spikes and some Si precipitates following
the contours of the grain boundaries in the Al (which has been etched
off). This is not surprising, because precipitation is a diffusion process,
after all, and diffusion along grain boundaries is faster then in the
bulk. |
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The right hand picture shows rather
large precipitates, almost taken up all the space there is in the contact
hole. |
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The question, of course, is: Does it
matter? We still have some Al in contact to our Si substrate, and
than we have Al in contact to the Si precipitates and the
Si precipitates in contact to the Si substrate. Plenty of
possibilities to run a current through the contact. |
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Right, but Al in Si is
an acceptor, and we must expect the Si precipitates to be saturated with
Al and thus heavily p-doped. |
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No big problem as long as the Si below the
contact is p-doped, too, but a big problem for n-doped Si
and small contacts. |
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In this case part of the contact area is now a
pn-junction, blocking current flow in one direction. |
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It is clear that the contact resistance always increases with
decreasing contact area, but if we have p-doped Si precipitates,
we have only part of the geometrical contact area for the contact to
n-type Si. |
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What we get as a function of the contact hole
size for the n-doped case is shown in the figure in red. |
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The message is clear: Contact resistance will be
too large at some point. So what do you do? |
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Without the Si, you get
spikes, with the Si you get precipitates and a contact resistance that
is too large. |
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There is no choice anymore: You need
a new material; in this case a diffusion barrier between the Si and the
Al. |
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Introduce, e.g., a thin layer of
Ti/TiN between the Si and the Al, and your contact
resistance problems are solved, as seen in the figure. If you also throw in
contact hole filling with
W-CVD, you now have a structure like the one on the
title page. |
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Except, of course, that now you have
to worry about how to make and structure this layer. How to measure how thick
it is, and if it has the required properties (assuming that you know
that). |
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You must worry if the new diffusion
barrier interferes with the reliability of the metallization (after all,
electromigration in the metal is one of
the major causes of premature device failures), and if can keep the additional
processes cheap. |
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In other words. Introducing a new
material is a long and cumbersome process. |
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And a frustrating one. Nobody tells
you, that TiN is it! You (meaning you and your team) find that out
yourself. And in that process you will test many materials, most of which will
not be the right ones. |
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Out they go - and with them many
hours of your time and a lot of (other peoples) money. |
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© H. Föll