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Note: It is
too tiresome to underline all vectors, and we will simply stop doing it except
if it is absolutely necessary. |
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Electron waves like all waves
experience diffraction effects in periodic structures like crystals. This is
best described in the reciprocal lattice of
the crystal in question. There are several ways to construct a reciprocal lattice from a space lattice. |
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Remember that a lattice - in contrast to a crystal - is a mathematical
construct. A lattice becomes becomes a crystal by putting a set of
atoms - the base of the crystal - at
every lattice point. |
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There are 14 different kinds
of lattices - the Bravais lattices - with different symmetries that
are sufficient to describe the lattice of any crystal. |
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If you are unsure about this topic,
refer to the appropriate chapter in
"Introduction to
Materials Science I" (in German) or in "Defects" (in
English) |
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Lets look at three definitions of the
reciprocal lattice, which are - of course - all equivalent but at different
levels of abstraction. This is elaborated in the link. |
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1. The reciprocal lattice is
the Fourier
transform of the space lattice. |
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2. The reciprocal lattice with
an elementary cell (EC) as defined by the
base vectors b1,2,3 is obtained from the space lattice
as defined by its base vectors a1,2,3 by the
equations |
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| b1 = 2p |
a2×
a3
ax × (ay · az )
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| b2 = 2p |
a3×
a1
ax × (ay · az )
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| b3 = 2p |
a1×
a2
ax × (ay · az )
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| ax × (ay · az
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= |
volume V of EC |
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3. The base vectors of the reciprocal
lattice can be constructed by drawing vectors perpendicular to the three
{100} planes of the space lattice and taking their length as 2p/dhkl with
dhkl = spacing between the lattice planes with Miller
indices {hkl}. |
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You will, of course,
never confuse the spacing between lattice planes with the spacing between
crystal planes, i.e. sheets of atoms, which may be
something different. |
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If a wave impinges on a crystal - and
it doesn't matter if it is an electromagnetic wave, e.g. X-rays, or an
electron, or neutron "wave" - it will be reflected at a particular
set of lattice planes {hkl} characterized by its reciprocal lattice
vector g only if the
so-called Bragg
condition is met. |
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Let the wave vector of the
incoming wave be k, the wave vector of the reflected wave is
k'. The Bragg condition correlates the three vectors involved -
k, k', and g - in the simplest
possible form: |
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There is no simpler relation correlating three vectors -
mother nature again makes life as easy as possible for us! |
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This Bragg condition is easily visualized: |
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If, and only if the three vectors involved form a closed triangle, is the Bragg condition met. If the
Bragg condition is not met, the incoming
wave just moves through the lattice and emerges on the other side of the
crystal (neglecting absorption). |
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So far we assumed implicitly that the diffraction
(or, in more general terms, the scattering) of
the incoming wave is elastic, i.e. the
magnitude of k' is identical to that of k, i.e.
| k| = |k'| -
which means that the diffracted wave has the same momentum, wavelength and
especially energy as the incoming wave. |
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This is not necessarily implied by Braggs law
- the equation k k' =
g can also be met if k' differs from
k by a reciprocal lattice vector; i.e. if scattering with
a change of energy takes place. This will become important later. |
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In X-ray analysis of crystals
we often deal with an (idealized) situation were one well-defined plane wave with fixed wavelength
impinges on a crystal, and the question is which set of lattice planes will
reflect the one incoming beam. |
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This question can be answered most easily in a
qualitative way by a geometric construction called the Ewald
construction which can be found
in the "Introduction to
Materials Science II" Hyperscript. |
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However, if we consider the diffraction effects
occurring to the free electrons contained in the crystal, we are looking at a
(quasi) continuum of wave vectors: We have all possible directions and many
wavelengths. |
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The question is now a bit different: We want to know which
particular wave vectors out of many (an infinite set, in fact) meet the Bragg
condition for a given crystal lattice plane. |
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This question can be answered most easily and
semi-quantitatively by a geometric construction called the Brillouin
construction. Lets look at it in a
simplified two-dimensional form. |
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If we construct
Wigner-Seitz
cells
in the reciprocal lattice as shown by the
pink lines, all wave vectors ending on the Wigner-Seitz cell walls will meet
the Bragg condition for the set of lattice planes represented by the cell
wall. |
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The Wigner-Seitz cells form a
nested system of polyhedra
which can be numbered according to size. These cells are called
Brillouin
zones (BZ); the smallest one is
called the 1. BZ, the next smallest one the 2. BZ, and so
on. |
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All wave vectors that end on a BZ, will fulfill the
Bragg condition and thus are diffracted. Of course, the origin must be at the
center of that BZ. |
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Wave vectors completely in the interior of the 1. BZ,
or in between any two BZs, will never get diffracted; they move pretty much as if
the potential would be constant, i.e. they behave very close to the solutions
of the free electron gas. |
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Of course, if we talk about diffraction in a
crystal, we assumed implicitly that the potential is no longer constant, but
periodic with the crystal. |
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The statement above is thus not trivial, but a first important
conclusion from diffraction geometry alone: We have good reasons (albeit no
ironclad justification) to believe that the free electron gas model is a
decent approximation for electrons with
wave vectors not ending on (or close to) a
Brillouin zone of the crystal in question. |
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We thus only have to consider what happens to the electrons
with wave vectors on or close to a BZ. In which properties do they
differ from electrons of the free electron gas model? |
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© H. Föll