5.2 The relaxation time approximation in the Boltzmann equation

At time t = 0 we will switch of all external forces of the system. By scattering the system reaches the thermodynamic equilibrium state again, which will be described in linear approximation by

(f t ) = (f t )scat = -f(r,k,t) -f0(r,k) τ(k)

(5.10)

f0(r,k) is the equilibrium distribution function.
The relaxation time τ(k) describes how fast the system reaches thermodynamic equilibrium again.
The solution of the relaxation process is:

f(r,k,t) -f0(r,k) = [f(r,k, 0) -f0(r,k)] e- t τ(k)

(5.11)

The essence for the following calculation is that this relaxation time does not depend on the external forces (This is a very strong assumption; it does not hold e.g. in the space charge region or for ”injection level spectroscopy”).
For steady state (f t ) = 0 we get

- (f t )field = rf,v + 1 kf,Fa = -f(r,k) -f0(r,k) τ(k)

(5.12)

This is the fundamental equation for the description of stationary processes in relaxation time approximation.
For small perturbations we evaluate in a series:

f(r,k) = f0(r,k) + f(1)(r,k) + f(2)(r,k) + ...

(5.13)

and consider only the linear terms leading to

v,rf0(r,k) + rf(1)(r,k) + 1 Fa,kf0(r,k) + kf(1)(r,k) = -f(1)(r,k) τ(k)

(5.14)

Since the gradients r and k depend already linearly on the perturbation the derivations of f(1) are of second order f(2) and are therefor neglected. We find:

rf0(r,k) = r ( 1 1 + eE(k)-μ(r) kT(r) ) = -f0 E (rμ + (E -μ)rT T )

(5.15)

and

kf0(r,k) = k ( 1 1 + eE(k)-μ(r) kT(r) ) = f0 E kE(k) = f0 E v

(5.16)

For an electrical field

F = qE

(5.17)

we finally get

-f(1)(r,k) τ(k) = f0 E (qE -rμ - (E -μ)r ln (T)) ,v

(5.18)

The three terms on the right hand side describe

An overview of the above described an other time consuming processes is discussed in the semiconductor script.