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For ω = ω0 we find for the inner energy
U = 3 ∫ dωD(ω) ℏω exp (ℏω kT ) - 1 = ℏω0 exp (ℏω0 kT ) - 13N.
and:
CV = dU dT = 3Nℏω (eℏω kT - 1) 2 eℏω kT ℏω kT .
For high temperatures we again get:
CV = 3Nk.
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