Exercise 6.1-1

Shuffling Fermi Functions

"Shuffling" Fermi distributions, while not really difficult, needs some practice and getting used to; it is good exercise to do it a few times (you may also consider to try it for some shuffling done before).
Show that the 1st laser condition
EFeEF h  ³  hn   ³  Eg
follows directly from
 =  [fe in C(E1 + hn, EFe , T)] · [fh in V(E1, EFh, T)]
[1 – fh in V(E 1, EF h, T)] · [1 – fe in C( E 1 + hn, EFe, T)]

Link to the solution

With frame With frame as PDF

go to 6.1.1 Interaction of Light and Electrons; Inversion

go to Einstein Coefficients

go to Solution to Exercise 6.1-1

© H. Föll (Semiconductors - Script)