 | 1. Is the electrical and magnetic field really in phase as shown in the drawing above? |
 | Yes it is - all serious sources agree even so the reasons given are mostly not obvious. The
real question, of course, is: why should this be a question at all? |
|  | Solving the Maxwell equations quite generally for the "wave" case,
simply gives solutions with no phase differences of the form: |
| |
E(r,t);
H(r,t) |
= E0; H0 · exp{i(kr –wt)} |
|
|
 | True enough. But this simple solution describes an infinitely extended electromagnetic plane wavesomething that does not exist. So let's look what happens for finite
waves that have a beginning at some point in space. |
|  | Not so easy for
light. The generation of a photon is always a quantum mechanical effect not covered by the Maxwell equations. However,
the equation above is valid for all electromagnetic waves. It is also valid, e.g.
for the radio waves produced by a simple dipole antenna and this is covered by the
Maxwell equations. We thus can look at the generation of a radio wave instead of a light wave; something easier to
conceive than the generation of a light wave by the transition of an electron from one energy level to another
one. |
|  | The figure below shows the principle. An AC current
is fed to a dipole, it drives charges to the two ends. Maximum current flows when there are no charges at the dipole
ends, we then have maximum magnetic fields and no electric field |
|  | The charges transported to the end of the dipole cause an electrical field that opposes current flow.
Eventually, at maximum charge and thus electrical field, current flow is zero and there is no magnetic field. |
| |
|
|  | The unavoidable conclusion is that at the place where
we make the wave - and it doesn't matter what kind of wavelength you envision - the
electrical field and the magnetic field are 90o out of
phase! |
 | Now we have a problem: far away from the "light
source" the two fields are in phase but where we make them they are out of phase! |
|  | The problem is solved when one
looks at the full set of equations (not easy). Far away from the dipole, in the far
field, we "see" a point source that emits a spherical wave and there is no phase difference, indeed.
Close to the dipole (measured in units of the wavelength), in the near field, we do
not see a point source but a complex geometry as sketched above. The fields in the
near field do not have spherical symmetry and phases right at the dipole are different by 90o,
indeed. |
|  | In mathematical terms, we superimpose a complicated
near field term with a general 1/rn dependence (n > 1 on a simple spherical wave. The
near-field term dominates close to the antenna. Since it decreases faster than the spherical wave term, for large
distances we can neglect the near-field term and are left with a spherical wave that appears to be a plane wave if you
only look in parts of space. |
 | You don't need to know this but you should be aware
that as soon as you leave the ideal realm of the simple plane wave without a beginning and an end, things tend to get
much more complicated. But things also tend to be much
more like what we actually know. |
|
© H. Föll (Advanced Materials B, part 1 - script)