Exercise 6.1-1

Shuffling Fermi Functions

"Shuffling" Fermi distributions, while not really difficult, needs some practice and getting used to; it is good exercise to do it a few times (you may also consider to try it for some shuffling done before).
Show that the 1st Laser condition
EFe – EFh  ³  Eg  ³  hn
follows directly from
 =  [1 – fh in V(E V, EFh, T)] · [1 – fe in C(E C, EFe, T)]
[fe in C(E C, EFe, T)] · [fh in V(E V, EFh, T)]

Link to the solution

With frame With frame as PDF

go to 6.1.1 LASER conditions

go to Einstein Coefficients

go to Solution to Exercise 6.1.1-1

© H. Föll (Semiconductor - Script)