# Exercise 6.1-1

# Shuffling Fermi Functions

| "Shuffling" Fermi distributions, while not really difficult, needs some practice and getting used to; it is good exercise to do it a few times (you may also consider to try it for some shuffling done before).
|  | Show that the 1st laser condition
EFe – EF h ³ hn ³ Eg
|  | follows directly from
Rse Rfa | = | [fe in C(E1 + hn, EFe , T)] · [fh in V(E1, EFh, T)] [1 – fh in V(E 1, EF h, T)] · [1 – fe in C( E 1 + hn, EFe, T)]
--- | --- | ---
| Link to the solution

With frame

6.1.1 Interaction of Light and Electrons; Inversion

Einstein Coefficients

Solution to Exercise 6.1-1

© H. Föll (Semiconductors - Script)